sql语句 实现两个表查询显示,有一个聚合函数count()
我有一个news表和一个comment表,我想查询news的所有内容和每条new的评论总数,该怎么写?我是用newid连接两个表的"selecttop10n.newId,...
我有一个news表和一个comment表,我想查询news的所有内容和每条new的评论总数,该怎么写?我是用newid连接两个表的
"select top 10 n.newId,count(c.*) from new as n join comment as c on c.newId=n.newId where n.newId=@id group by n.newId order by count(c.*) desc";
这样貌似不对 展开
"select top 10 n.newId,count(c.*) from new as n join comment as c on c.newId=n.newId where n.newId=@id group by n.newId order by count(c.*) desc";
这样貌似不对 展开
5个回答
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这个我们首先禅局拍可以对2张表按newsid进行贺羡连接,
然后按腊指new进行分组计数即可。
select n.newId, count(c.*)
from new as n
left join comment as c on c.newId = n.newId
group by n.newId
然后按腊指new进行分组计数即可。
select n.newId, count(c.*)
from new as n
left join comment as c on c.newId = n.newId
group by n.newId
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select top 10 n.*,d.p from new n, (select count(*) as p,newId from comment group by newId) d where n.newId=@id and n.newId = d.newId order by d.p desc
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select n.newId, count(c.*)
from new as n
left join comment as c on c.newId = n.newId
group by n.newId
order by count(c.*) desc
应棚物该没坦和物问题的让液。
from new as n
left join comment as c on c.newId = n.newId
group by n.newId
order by count(c.*) desc
应棚物该没坦和物问题的让液。
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select
News.*
,C.Num
from
News
AS N
inner
join
(
select
NewID,count(*)
AS
Num
from
comment group
by
NewID
)
AS
C
on
N.ID=C.NewIDorder
by
C.Num
DESC
News.*
,C.Num
from
News
AS N
inner
join
(
select
NewID,count(*)
AS
Num
from
comment group
by
NewID
)
AS
C
on
N.ID=C.NewIDorder
by
C.Num
DESC
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