计算:(1)18−6÷(−2)×(−13);?
展开全部
(1)18−6÷(−2)×(−
1
3)
=18-(-3)×(-[1/3])
=18-(3×[1/3])
=18-1
=17;
(2)(−3)2×[−
2
3+(−
5
9)]
=9×[-[2/3]+(-[5/9])]
=9×(-[2/3])+9×(-[5/9])
=(-6)+(-5)
=-(6+5)
=-11;
(3)(
1
4−
1
2−
1
8)×16
=[1/4]×16-[1/2]×16-[1/8]×16
=4-8-2
=4+(-8)+(-2)
=4+[(-8)+(-2)]
=4+(-10)
=-(10-4)
=-6;
(4)−14−
1
7×[2−(−3)2]
=-1-[1/7]×(2-9)
=-1-[1/7]×[2+(-9)]
=-1-[1/7]×(-7)
=-1-(-1)
=-1+1
=0.,6,计算:
(1) 18−6÷(−2)×(− 1 3 ) ; (2) (−3 ) 2 ×[− 2 3 +(− 5 9 )] ;
(3) ( 1 4 − 1 2 − 1 8 )×16 ; (4) − 1 4 − 1 7 ×[2− (−3) 2 ] .
1
3)
=18-(-3)×(-[1/3])
=18-(3×[1/3])
=18-1
=17;
(2)(−3)2×[−
2
3+(−
5
9)]
=9×[-[2/3]+(-[5/9])]
=9×(-[2/3])+9×(-[5/9])
=(-6)+(-5)
=-(6+5)
=-11;
(3)(
1
4−
1
2−
1
8)×16
=[1/4]×16-[1/2]×16-[1/8]×16
=4-8-2
=4+(-8)+(-2)
=4+[(-8)+(-2)]
=4+(-10)
=-(10-4)
=-6;
(4)−14−
1
7×[2−(−3)2]
=-1-[1/7]×(2-9)
=-1-[1/7]×[2+(-9)]
=-1-[1/7]×(-7)
=-1-(-1)
=-1+1
=0.,6,计算:
(1) 18−6÷(−2)×(− 1 3 ) ; (2) (−3 ) 2 ×[− 2 3 +(− 5 9 )] ;
(3) ( 1 4 − 1 2 − 1 8 )×16 ; (4) − 1 4 − 1 7 ×[2− (−3) 2 ] .
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询