Question

c++问题 关于结构error: expected primary-expression before '{' token

帮帮忙吧，初学者，可这个程序总也编译不了，自学真麻烦呀
#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
int number(0);
double number1(0);
double number2(0);
struct Convert
{
char convert_name[100];
double convert_rate;
};
Convert convert[3];
convert[0]={"yuan to dollar",0.125};
convert[1]={"dollar to pound",2};
convert[2]={"yuan to pound",0.0625};
cout<<"choose a way to convert money"<<endl<<"1.yuan to dollar"<<endl<<"2.dollar to pound"<<endl<<"3.yuan to pound";
cin>>number;
cout<<"please enter the type that you want to convert";
cin>>number1;
if(number<3&&number>=0)
number2=number1*convert[number-1].couvert_rate;
else
cout<<"sorry ,you entered a wrong number";
cout<<number1<<convert[number-1].convert_name<<" is "<<number2;

system("PAUSE");
return EXIT_SUCCESS;
}
下面是错误信息
Compiler: Default compiler
Building Makefile: "C:\Users\shanliho\Documents\Makefile.win"
Executing make...
make.exe -f "C:\Users\shanliho\Documents\Makefile.win" all
g++.exe -c main.cpp -o main.o -I"lib/gcc/mingw32/3.4.2/include" -I"include/c++/3.4.2/backward" -I"include/c++/3.4.2/mingw32" -I"include/c++/3.4.2" -I"include"

main.cpp: In function `int main(int, char**)':

main.cpp:17: error: expected primary-expression before '{' token

main.cpp:17: error: expected `;' before '{' token

main.cpp:18: error: expected primary-expression before '{' token

main.cpp:18: error: expected `;' before '{' token

main.cpp:19: error: expected primary-expression before '{' token

main.cpp:19: error: expected `;' before '{' token

main.cpp:25: error: 'struct main(int, char**)::Convert' has no member named 'couvert_rate'

make.exe: *** [main.o] Error 1

Execution terminated

Answer 1

如下：

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

int number(0);

double number1(0);

double number2(0);

struct Convert

{

char convert_name[100];

double convert_rate;

};

Convert convert[3] = {{{"yuan to dollar"},0.125},{"dollar to pound",2},{"yuan to

pound",0.0625}};

cout<<"choose a way to convert money"<<endl<<"1.yuan to dollar"<<endl<<"2.dollar to

pound"<<endl<<"3.yuan to pound";

cin>>number;

cout<<"please enter the type that you want to convert";

cin>>number1;

if(number<3&&number>=0)

number2=number1*convert[number-1].convert_rate;

else

cout<<"sorry ,you entered a wrong number";

cout<<number1<<convert[number-1].convert_name<<" is "<<number2;

system("PAUSE");

return EXIT_SUCCESS;

}

扩展资料：

C++常用函数：

int abs(int x)：求整数x的绝对值 

double acos(double x)：计算arcos(x)的值 

double asin(double x)：计算arsin(x)的值 

double atan(double x)：计算arctan(x)的值 

double cos(double x)：计算cos(x)的值 

double cosh(double x)：计算x的双曲余弦cosh(x)的值 

double exp(double x)：求的值 

double fabs(double x)：求实数x的绝对值 

double fmod(double x)：求x/y的余数 

long labs(long x)：求长整型数的绝对值 

double log(double x)：计算In(x)的值

double log10(double x)：计算的值 

double modf(double x, double *y)：取x的整数部分送到y所指向的单元格中 

double pow(double x, double y)：求x的y次幂的值 

double sin(double x)：计算sin(x)的值 

double tan(double x)：计算tan(x)的值 

void abort(void)：终止程序执行   

void exit(int)：终止程序执行   

double atof(const char *s)：将s所指向的字符串转换成实数 

int atoi(const char *s)：将s所指向的字符串转换成整数 

long atol(const char *s)：将s所指的字符串转换成长整数 

int rand(void)：产生一个随机整数 

Answer 2

改好了，自己看吧。主要是字符数组初始化的问题，记住只有在定义字符数组的时候才可以用字符串给字符数组赋值。还有一个拼写错误，我也改过来了
#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
int number(0);
double number1(0);
double number2(0);
struct Convert
{
char convert_name[100];
double convert_rate;
};
Convert convert[3] = {{{"yuan to dollar"},0.125},{"dollar to pound",2},{"yuan to pound",0.0625}};
cout<<"choose a way to convert money"<<endl<<"1.yuan to dollar"<<endl<<"2.dollar to pound"<<endl<<"3.yuan to pound";
cin>>number;
cout<<"please enter the type that you want to convert";
cin>>number1;
if(number<3&&number>=0)
number2=number1*convert[number-1].convert_rate;
else
cout<<"sorry ,you entered a wrong number";
cout<<number1<<convert[number-1].convert_name<<" is "<<number2;

system("PAUSE");
return EXIT_SUCCESS;
}

Answer 3

是因为在函数调用时 括号里的参数前面还加了变量类型 去掉这个变量类型就行了
（至少我的错误是这样的。。。其他情况就不清楚了）

Answer 4

#include <studio.h>
void main()
{
int a=5,b=3;
scanf("d%,d%",&a,&b);
x=a*b;
printf("d%,d%,d%",a,b,x)
}