Question

高数积分 求大神 ∫(x^2)*e^(x^2)dx

Answer 1

答：非常复杂...

可以参考下面的链接解答：
http://zhidao.baidu.com/link?url=Q9SgPTz6S-9ABdIIS7li0H2sHTDsGjHT9lgH9H0NwS7M-uxIgNJqzfTnPh4xa841DJsWZAdv2tAYSQnpFr4Eyq

∫x^2e(x^2)dx
=(1/2)∫xe^(x^2)dx^2
=(1/2)∫xd(e^x^2)
=(1/2)xe^(x^2)-(1/2)∫e^x^2d(x^2)^(1/2)
=(1/2)xe^(x^2)-(1/4)∫e^x^2dx^2/(x^2)^(1/2)

∫e^x^2dx^2/(x^2)^(1/2)
取t=(x^2)
=∫e^tdt/t^(1/2)
e^t=1+t+t^2/2!+t^3/3!+..+t^n/n!
=∫[1/t^(1/2)+t^(1/2)+t^(3/2)/2!+t^(5/2)/3!+..+t^(n-1/2)/n!]dt
=2t^(1/2)+(2/3)t^(3/2)+(2/5)t^(5/2)/2!+(2/7)t^(7/2)/3!+..+(n+1/2)*t^(n+1/2)/n!+C

∫x^2e^(x^2)dx
=(1/2)xe^(x^2)-(1/4)[2*x+(2/3)x^3+(2/5)x^5/2!+(2/7)x^7/3!+..+(n+1/2)x^(2n+1)/n!] +C