3个回答
展开全部
x" - 2( 1 + √2 )x + 2√2 = 0
x" - 2( 1 + √2 )x + ( 1 + √2 )" + 2√2 - ( 1 + 2 + 2√2 ) = 0
( x - 1 - √2 )" - ( 1 + 2 ) = 0
( x - 1 - √2 )" - ( √3 )" = 0
( x - 1 - √2 - √3 )( x - 1 - √2 + √3 ) = 0
解方程
x1 = 1 + √2 + √3 ,
x2 = 1 + √2 - √3
x" - 2( 1 + √2 )x + ( 1 + √2 )" + 2√2 - ( 1 + 2 + 2√2 ) = 0
( x - 1 - √2 )" - ( 1 + 2 ) = 0
( x - 1 - √2 )" - ( √3 )" = 0
( x - 1 - √2 - √3 )( x - 1 - √2 + √3 ) = 0
解方程
x1 = 1 + √2 + √3 ,
x2 = 1 + √2 - √3
展开全部
X方-2(1+根号2)x+2根号2=0
X方-2(1+根号2)x+2根号2+3-3=0
X方-2(1+根号2)x+(1+根号2)方-3=0
(X-1-根号2)方=3
X-1-根号2=根号3
X=4+根号2
X方-2(1+根号2)x+2根号2+3-3=0
X方-2(1+根号2)x+(1+根号2)方-3=0
(X-1-根号2)方=3
X-1-根号2=根号3
X=4+根号2
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展开全部
x^2-2(1+√2)x+2√2=0
x^2-2(1+√2)x+2√2+3-3=0
x^2-2(1+√2)x+(1+√2)^2-3=0
(x-1-√2)^2=3
x=4+√2
x^2-2(1+√2)x+2√2+3-3=0
x^2-2(1+√2)x+(1+√2)^2-3=0
(x-1-√2)^2=3
x=4+√2
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