Question

|a-1|与(b-1)平方互为相反数,求x.x/a(b+1)+x/(a+1)(b+2)+x/(a

2)(b+3)+………+x/(a+2014)(b+2015)=2014

Answer 1

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Answer 2

|a-1|与(b-1)平方互为相反数
a=1
b=1
x/a(b+1)+x/(a+1)(b+2)+x/(a+2)(b+3)+………+x/(a+2014)(b+2015)=2014
x[1/1*2+1/2*3+……+1/2015*2016]=2014
x(1-1/2+1/2-1/3+……+1/2015-1/2016)=2014
x(1-1/2016)=2014
2015/2016x=2014
x=2016*2014/2015=(2015+1)*(2015-1)/2015=2015-1/2015

x=2014又2015分之2014