七年级数学题,求答案,给好评!
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(-2x-1)²(2x-1)²-16(x+3)²(x-3)²
=(1-4x²)²-16(x²-9)²
=[1-4x²-4(x²-9)][(1-4x²+4(x²-9)]
=(1-4x²-4x²+36)(1-4x²+4x²-36)
=(37-8x²)(-35)
=-35(8x²-37)
=(1-4x²)²-16(x²-9)²
=[1-4x²-4(x²-9)][(1-4x²+4(x²-9)]
=(1-4x²-4x²+36)(1-4x²+4x²-36)
=(37-8x²)(-35)
=-35(8x²-37)
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2015-10-15
展开全部
(-2x-1)²(2x-1)²-16(x+3)²(x-3)²
=(2x+1)²(2x-1)²-16(x+3)²(x-3)²
=[(2x+1)(2x-1)]²-[4(x+3)(x-3)]²
=(4x²-1)²-(4x²-36)²
=[(4x²-1)+(4x²-36)][(4x²-1)-(4x²-36)]
=(8x²-37)*35
=280x²-1295
=(2x+1)²(2x-1)²-16(x+3)²(x-3)²
=[(2x+1)(2x-1)]²-[4(x+3)(x-3)]²
=(4x²-1)²-(4x²-36)²
=[(4x²-1)+(4x²-36)][(4x²-1)-(4x²-36)]
=(8x²-37)*35
=280x²-1295
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