Question

Java 语句问题 请问下 key iv是如何怎么运算 看不懂Java啊 请大神帮忙

paramString1 = 13101102323
paramString2 = 5201314

public static String az(String paramString1, String paramString2)
{
Object localObject = "";
byte[] arrayOfByte1 = new byte[8];
try
{
byte[] arrayOfByte2 = paramString1.getBytes("UTF-8");
if (arrayOfByte2.length < 8)
{
System.arraycopy(arrayOfByte2, 0, arrayOfByte1, 0, arrayOfByte2.length);
for (int i = arrayOfByte2.length; i < 8; i++)
arrayOfByte1[i] = 0;
}
System.arraycopy(arrayOfByte2, 0, arrayOfByte1, 0, 8);
Cipher localCipher = Cipher.getInstance("DES/CBC/PKCS5Padding");
localCipher.init(1, new SecretKeySpec(arrayOfByte1, "DES"), new IvParameterSpec(arrayOfByte1));
String str = d.h(localCipher.doFinal(paramString2.getBytes("UTF-8")));
localObject = str;
return localObject;
}
catch (Exception localException)
{
while (true)
localException.printStackTrace();
}
}
}
请问下
paramString1 = 13101102323
paramString2 = 5201314
key iv如何计算的啊 不懂Java啊大神

Answer 1

key iv是对称算法么？没看懂不过给你一个注释好的代码

public static String az(String paramString1, String paramString2) {
		//声明object对象
		Object localObject = "";
		//声明8位的byte对象
		byte[] arrayOfByte1 = new byte[8];
		try {
			//转换编码格式为UTF-8
			byte[] arrayOfByte2 = paramString1.getBytes("UTF-8");
			//判断长度是否为8
			if (arrayOfByte2.length < 8) {
				//为使处理字符长度为8位，进行数组复制将arrayOfByte2的值复制给arrayOfByte1
				System.arraycopy(arrayOfByte2, 0, arrayOfByte1, 0,
						arrayOfByte2.length);
				//为arrayOfByte1数组空位补0
				for (int i = arrayOfByte2.length; i < 8; i++)
					arrayOfByte1[i] = 0;
			}
			//为使处理字符长度为8位，进行数组复制将arrayOfByte2的值复制给arrayOfByte1
			System.arraycopy(arrayOfByte2, 0, arrayOfByte1, 0, 8);
			//声明加密处理类，并指定转换名称
			Cipher localCipher = Cipher.getInstance("DES/CBC/PKCS5Padding");
			//用密钥和向量初始化此加密对象
			localCipher.init(1, new SecretKeySpec(arrayOfByte1, "DES"),
					new IvParameterSpec(arrayOfByte1));
			//???不懂????
			String str = d
					.h(localCipher.doFinal(paramString2.getBytes("UTF-8")));
			localObject = str;
			return localObject;
		} catch (Exception localException) {
			while (true)
				localException.printStackTrace();
		}
	}