Question

求助 matlab算四元一次方程

哪位大哥能帮我算出一个四元一次方程组啊！！ a+0.907b+0.807c+0.166d=0.561
0.907a+b+0.879c+0.022d=0.598
0.801a+0.879b+c+(-0.010)d=0.582
0.166a+0.022b+(-0.010)c+d=0.065
这个用矩阵不会算 我不是学数学的 急求这结果写论文！！如哪位能帮忙算出来 不胜感激！！！！

Answer 1

[a,b,c,d]=solve(...
'a+0.907*b+0.807*c+0.166*d=0.561',...
'0.907*a+b+0.879*c+0.022*d=0.598',...
'0.801*a+0.879*b+c+(-0.010)*d=0.582',...
'0.166*a+0.022*b+(-0.010)*c+d=0.065')

Answer 2

solve('a+0.907*b+0.807*c+0.166*d=0.561','0.907*a+b+0.879*c+0.022*d=0.598','0.801*a+0.879*b+c+(-0.010)*d=0.582','0.166*a+0.022*b+(-0.010)*c+d=0.065')

Answer 3

a=0.0479

    b=0.3303

    c=0.2538

    d=0.0523

程序如图