怎么算这道题
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原式=1/2*[(3-1)(3+1)](3^2+1)(3^4+1)(3^8+1)*...*(3^64+1)
=1/2(3^2-1)(3^2+1)(3^4+1)(3^8+1)*...*(3^64+1)
=1/2[(3^2-1)(3^2+1)](3^4+1)(3^8+1)*...*(3^64+1)
=1/2(3^4-1)(3^4+1)(3^8+1)*...*(3^64+1)
=1/2[(3^4-1)(3^4+1)](3^8+1)*...*(3^64+1)
=1/2(3^8-1)(3^8+1)*...*(3^64+1)
=.....
=1/2*(3^128-1)
=(3^128-1)/2
=1/2(3^2-1)(3^2+1)(3^4+1)(3^8+1)*...*(3^64+1)
=1/2[(3^2-1)(3^2+1)](3^4+1)(3^8+1)*...*(3^64+1)
=1/2(3^4-1)(3^4+1)(3^8+1)*...*(3^64+1)
=1/2[(3^4-1)(3^4+1)](3^8+1)*...*(3^64+1)
=1/2(3^8-1)(3^8+1)*...*(3^64+1)
=.....
=1/2*(3^128-1)
=(3^128-1)/2
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