Question

ajax怎么解析后台传过来的json数据

Answer 1

$.ajax({
type: "GET",
traditional: true,
url: url,
//dataType: "json",
data: dataParam,
success: function (res) {
var data=evla('('+res+')');
},
error: function (XMLHttpRequest, textStatus, errorThrown) {
common.errorResponse(XMLHttpRequest, textStatus, errorThrown);
}
});