请问第九题选什么
2个回答
2017-06-06
展开全部
sin(7π/12-x)=1/3
sin[π/2-(x-π/12)] = 1/3
cos(x-π/12) = 1/3
cos(2x-π/6) = 2* cos²(x-π/12) - 1 = 2*(1/3)² - 1 = -7/9
sin[π/2-(x-π/12)] = 1/3
cos(x-π/12) = 1/3
cos(2x-π/6) = 2* cos²(x-π/12) - 1 = 2*(1/3)² - 1 = -7/9
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