Question

如何将一个数组分成N个等分的数组

Answer 1

把Java中的集合，数组，字符串整合成一个统一的api。很类似JQuery中的著名的$函数。

看例子吧：

// 产生 0, 1, 2, 3, 4序列

List list = $(5).toList();

// 指定开始结束的序列 10, 11, 12, 13, 14

List list2 = $(10, 15).toList();

// 产生随机数序列

List randomIntegers = $(new Random(), 100).samples(50).sort().toList();

// jion方法，我太喜欢了。"4->3->2->1->0"

$(5).reverse().join("->");

// join() any iterable to a String

$(array).join();

$(list).join();

$(set).join();

// join() works also for 'range' type

$(5, 10).join(); // "56789"

$('a', 'd').join("-"); // "a-b-c-d"

// and even on strings, StringBuilders, etc

$("aaa").join(" "); // "a a a"

// repeat Strings, but it works also for any Iterable/Collection and
Array

String repeat = $("abc").repeat(3).join(" "); // "abc abc abc"

// convert Long[] to long[], while sorting it

Long[] aLongArray = { 42L, 84L };

long[] longs = $(aLongArray).sort().toLongArray();

// fluent interface: convert a primitive int array to ArrayList, in the
reversed order

int[] array = { 4, 2, -5 };

List list = $(array).sort().reverse().toList();

// you can even unbox a short[] array to long[] (since it doesn't cause a
loss of precision)

short[] shorts = { 42, 42, 42 };

long[] $(shorts).toLongArray();

// syntactic sugar

$("a string").size(); // "a string".length()

$(aCollection).size(); // aCollection.size()

$(anArray).size(); // anArray.length

$(array).toString(); // calls Arrays.toString()

// for loop以前这么写

for (int i = 0; i < 10; i++) {

}

// 现在只需要

for (int i : $(10)) {

}

//查找 排序 取出最大最小值

$(any).indexOf(T)

$(any).sort(Comparator)

$(any).max(Comparator)

$(any).min(Comparator)