Question

数学题目，请你们帮帮忙！！谢谢！！

接下来怎么代进去？？用基本不等式求解，谢谢你们！

Answer 1

y=5-x
1/(x+1) +1/(y+2)

=1/(x+1) + 1/(5-x+2)
=1/(x+1) + 1/(7-x)
≥ 2/√[(x+1).(7-x)]
= 2/√( 7+6x-x^2)
= 2/√[ 16- (x-3)^2]
≥ 1/2
min [ 1(x+1) +1/(y+2) ] =1/2