Question

数学不定积分问题，求解答

如图所示，求解，麻烦详细过程

Answer 1

详细过程如图rt……希望能帮到你

Answer 2

∫<0, π>|cosx|dx = ∫<0, π/2>cosxdx + ∫<π/2, π>(-cosx)dx
= [sinx]<0, π/2> + [-sinx]<π/2, π> = 1 + 1 = 2