数学问题:2分之1a的2次方b-5ac-(3a的2次方-a的2次方b)+(3ac-4a的2次方c)
1个回答
展开全部
2分之1a的渗段2次方b-5ac-(3a的2次方-a的2次方b)+(3ac-4a的2次方c)搜闹
=(a²b-5ac)/2-2(3a²-a²b)/2+2(3ac-4a²c)/2
=(a²b-5ac-6a²+2a²世喊罩b+6ac-8a²c)/2
=(3a²b+ac-6a²-8a²c)/2
=[3a²(b-2)+ac(1-8a)]/2
={3a²(2-2)+(-1)(-2)[1-8*(-1)]}/2
=[0+2*(1+8)]/2
=2*9/2
=9
[²:Alt+小键盘178,³:Alt+小键盘179]
=(a²b-5ac)/2-2(3a²-a²b)/2+2(3ac-4a²c)/2
=(a²b-5ac-6a²+2a²世喊罩b+6ac-8a²c)/2
=(3a²b+ac-6a²-8a²c)/2
=[3a²(b-2)+ac(1-8a)]/2
={3a²(2-2)+(-1)(-2)[1-8*(-1)]}/2
=[0+2*(1+8)]/2
=2*9/2
=9
[²:Alt+小键盘178,³:Alt+小键盘179]
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询