Question

|x|=4;|y|=2/1;x+y<0;x+y=

若|x-1/2|+(2y+1)^2=0,那么x+y=_____.
-2的相反数与-1/2的倒数和的绝对值等于____.
若|a|=4,|b|=3,且a,b异号,则|a-b|=_____.
若a＜b,则|b-a+1|-|a-b|=____.
如果x＜y＜0,则花间|x|/x + |xy|/xy的结果为____.

Answer 1

若|x-1/2|+(2y+1)^2=0,那么x+y=__0___.x=1/2,y=-1/2,x+y=0
-2的相反数与-1/2的倒数和的绝对值等于_0___.
2+（-2）=0若|a|=4,|b|=3,且a,b异号,则|a-b|=__7___.
a=4,b=-3
|a-b|=7
a=-4,b=3
|a-b|=7若a＜b,则|b-a+1|-|a-b|=_1___.
b-a>0
b-a+1-(b-a)
=1如果x＜y＜0,则花间|x|/x + |xy|/xy的结果为_0___.
x0
原式=-1+1=0