-x³++x²+6x-5=0求x
2个回答
展开全部
f(x) = -x³+x²+6x-5
f(0.5) = -1.875, f(1) = 1
f(0.8) = -0.072, f(0.85) = 0.208
f(0.81) = -0.0153, f(0.82) = 0.041
f(0.812) = -0.00404, f(0.813) = 0.0016
f(0.8127) = -0.0000918, x ≈ 0.8127
f(0.5) = -1.875, f(1) = 1
f(0.8) = -0.072, f(0.85) = 0.208
f(0.81) = -0.0153, f(0.82) = 0.041
f(0.812) = -0.00404, f(0.813) = 0.0016
f(0.8127) = -0.0000918, x ≈ 0.8127
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展开全部
f(x) = -x³+x²+6x-5
f(0.5) = -1.875, f(1) = 1
f(0.8) = -0.072, f(0.85) = 0.208
f(0.81) = -0.0153, f(0.82) = 0.041
f(0.812) = -0.00404, f(0.813) = 0.0016
f(0.8127) = -0.0000918, x ≈ 0.8127
f(0.5) = -1.875, f(1) = 1
f(0.8) = -0.072, f(0.85) = 0.208
f(0.81) = -0.0153, f(0.82) = 0.041
f(0.812) = -0.00404, f(0.813) = 0.0016
f(0.8127) = -0.0000918, x ≈ 0.8127
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