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x-4×(-5)×二分之五+(-2)×(-3)的平方=7x求x
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x=16/3
x-4×(-5)×5/2+(-2)×(-3)^2
=x-(-50)+(-2)×9
=x+50+(-18)
=x+50-18
=x+32
=7x
解得x=16/3
x-4×(-5)×5/2+(-2)×(-3)^2
=x-(-50)+(-2)×9
=x+50+(-18)
=x+50-18
=x+32
=7x
解得x=16/3
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