13.解方程 (11)/(x-7)-1/(x-5)=1/(x-6?
3个回答
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11/(x-7)-1/(x-5)=1/(x-6)
解:11×(x-5)(x-6)-(x-7)(x-6)=(x-7)(x-5)
解:11×(x²-11x+30)-(x²-13x+42)=x²-12x+35
11x²-121x+330-x²+13x-42-x²+12x-35=0
9x²-96x+253=0
(3x-4)²-3=0
(3x-4)=±√3
x₁=(√3+4)/3,x₂=(4-√3)/3
解:11×(x-5)(x-6)-(x-7)(x-6)=(x-7)(x-5)
解:11×(x²-11x+30)-(x²-13x+42)=x²-12x+35
11x²-121x+330-x²+13x-42-x²+12x-35=0
9x²-96x+253=0
(3x-4)²-3=0
(3x-4)=±√3
x₁=(√3+4)/3,x₂=(4-√3)/3
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展开全部
11/(x-7)-1/(x-5)=1/(x-6)
解:11( x-5)/(x-5)(x-7)-(x-7)/(x-7)(x-5)=1/( x-6)
11x-55/ (x²-12x+35)-( x-7)/( x²-12x+35)=1/ x-6
11x-55-( x-7)=( x²-12x+35)/ x-6
(10x-48)( x-6)= x²-12x+35
10x²-108x+288= x²-12x+35
9x²-96x+253=0
(3x-4)²-3=0
(3x-4)=±√3
x₁=(4+√3)/3,x₂=(4-√3)/3
解:11( x-5)/(x-5)(x-7)-(x-7)/(x-7)(x-5)=1/( x-6)
11x-55/ (x²-12x+35)-( x-7)/( x²-12x+35)=1/ x-6
11x-55-( x-7)=( x²-12x+35)/ x-6
(10x-48)( x-6)= x²-12x+35
10x²-108x+288= x²-12x+35
9x²-96x+253=0
(3x-4)²-3=0
(3x-4)=±√3
x₁=(4+√3)/3,x₂=(4-√3)/3
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