Question

大家帮忙看看 很简单的个问题

#include <stdio.h>
main()
{ static char *a,*b="vhgfj";
static char*c=a;
for(;*b!='\0';b++)
*a++=*b;
*a='\0';
printf("%s\n",c);
}
意思是把b给a；c=a 然后通过c把a输出来 怎么不行啊

Answer 1

#include <stdio.h>
#include <string.h>

int main(void)
{
char *a = new char[10];
char *b = new char[10];
char *c = NULL;
c = b;

strcpy(b, "afdsf");

for( ; *b!='\0'; b++)
{
*a = *b;
}

*a='\0';

printf("%s\n",c);

delete []a;
delete []b;

return 0;
}
给你几句话：
1 习惯要好
2 不能试图给空的指针赋值
3 static的概念得清晰

Answer 2

a没有指向合法的空间，修改如下：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
main()
{ static char *a,*b="vhgfj";
static char*c;
a=(char*)malloc(sizeof(char)*strlen(b));
c=a;
for(;*b!='\0';b++)
*a++=*b;
*a='\0';
printf("%s\n",c);
free(c);
}