Question

初一 数学 快快快，急急急，明天要交的！ 请详细解答,谢谢! (29 19:48:13)

将下列各式分解因式：
20(x-y)2+10(x-y)+1

Answer 1

令X_Y=T 再把20提出来 把关于T的项写成完全平方形式 最后再用平方差的逆推即可

Answer 2

20(x-y)²+10(x-y)+1
=25(x-y)²+10(x-y)+1-5(x-y)²
=[5(x-y)+1]²-5(x-y)²
=[5(x-y)+1+√5(x-y)][5(x-y)+1-√5(x-y)]
=[(5+√5)(x-y)+1][(5-√5)(x-y)+1]

Answer 3

=40x-40y+10x-10y+1
=50x-50y+1

Answer 4

50（x-y)+1