Question

怎样实现同时监听多个EditText

Answer 1

/*

*要求一个ACTIVITY中的多个edittext都填写有内容才能按Button进入下一步的实现

*/

import android.os.Bundle;

import android.app.Activity;

import android.content.SharedPreferences.Editor;

import android.text.Editable;

import android.text.TextWatcher;

import android.util.Log;

import android.view.Menu;

import android.widget.Button;

import android.widget.EditText;

public class MainActivity extends Activity {

private EditText etONE;

private EditText etTWO;

private EditText etTHREE;

private Button btn;

@Override

protected void onCreate(Bundle savedInstanceState) {

super.onCreate(savedInstanceState);

setContentView(R.layout.activity_main);

etONE = (EditText)findViewById(R.id.etOne);

etTWO = (EditText)findViewById(R.id.etTwo);

etTHREE = (EditText)findViewById(R.id.etThree);

btn = (Button)findViewById(R.id.btn);

//为EditText绑定监听器

textChange tc1 = new textChange();

etONE.addTextChangedListener(tc1);

etTWO.addTextChangedListener(tc1);

etTHREE.addTextChangedListener(tc1);

}

//EditText监听器

class textChange implements TextWatcher {

@Override

public void afterTextChanged(Editable arg0) {

}

@Override

public void beforeTextChanged(CharSequence arg0, int arg1, int arg2,

int arg3) {

}

@Override

public void onTextChanged(CharSequence cs, int start, int before,

int count) {

boolean Sign1 = etONE.getText().length() > 0;

boolean Sign2 = etTWO.getText().length() > 0;

boolean Sign3 = etTHREE.getText().length() > 0;

if (Sign1&Sign2&Sign3) {

btn.setText("BINGO");

btn.setEnabled(true);

}

//在layout文件中，对Button的text属性应预先设置默认值，否则刚打开程序的时候Button是无显示的

else {

btn.setText("请填写好内容");

btn.setEnabled(false);

}

}

}

}