Question

c#如何OpenFileDialog按钮上传图片到PictureBox

已写按钮代码
string filepath = "";
OpenFileDialog fileName = new OpenFileDialog ();
fileName.InitialDirectory = Application.StartupPath;
if (fileName.ShowDialog() == DialogResult.OK)
filepath = fileName.FileName;

Answer 1

OpenFileDialog fd = new OpenFileDialog();
fd.Filter = "jpg|*.jpg";
if(fd.ShowDialog()== System.Windows.Forms.DialogResult.OK)
{
this.pictureBox1.ImageLocation = fd.FileName;
}

追问

图片显示不出来啊、

追答

你换个图片试试，有的图片好象是不能显示的。

追问

都不行 。。