![](https://iknow-base.cdn.bcebos.com/lxb/notice.png)
数学问题
1个回答
展开全部
f(x)=2x-1
g(x)=x^2 (x>=0)
g(x)=-1 (x<0)
f[g(x)]
=2x^2-1 (x>=0)
f[g(x)]
=2(-1)-1
=-3 (x<0)
f(x)>=0
2x-1>=0
x>=1/2
g[f(x)]
=(2x-1)^2
=4x^2-4x+1 (x>=1/2)
f(x)<0
2x-1<0
x<1/2
g[f(x)]
=-1 (x<1/2)
g(x)=x^2 (x>=0)
g(x)=-1 (x<0)
f[g(x)]
=2x^2-1 (x>=0)
f[g(x)]
=2(-1)-1
=-3 (x<0)
f(x)>=0
2x-1>=0
x>=1/2
g[f(x)]
=(2x-1)^2
=4x^2-4x+1 (x>=1/2)
f(x)<0
2x-1<0
x<1/2
g[f(x)]
=-1 (x<1/2)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询