Question

这道题怎么做？要过程写全拜

Answer 1

∵△ABC≌△ADE
∴∠CAB＝∠EAD ∠ACB=∠DEA
∵∠EAB=120° ∠CAD=10°
∴∠CAB＝∠EAD=55°
∴∠ACB=∠AED=110°
∵四边形ABFE内角和360°
∴∠BFD=75°①
∵∠AGB=∠DGF ∠B=∠D
∴△ACB∽△FCD
∴∠GFD=∠GAB=∠GAC+∠BAC=10°+55°=65°
∴∠DGB=90°②

Answer 2

角BAD=角CAB=(120-10)/2=55度, 角B=角D=25度, 角CAD=10度
角DGB=角GAB+角B=10+55+25=90度,
角DFB=90-25=65度

Answer 3

∠EAD=∠CAB=（120°-10°）÷2=55°，∠E=∠ACB=180°-25°-55°=100°
∠FCA=180°-100°=80°
四边形ACFE的内角和=360°=∠E100°+∠EAC65°+∠ACF80°+180°-∠DFB=360°
∠DFB=115°
∠DGB=∠DFB+∠D=115°+25°=140°

Answer 4

稍等，我在纸上把答案写给你

追答

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