Question

高等数学微积分求第三小题

Answer 1

3. y = x 斜率为 k = 1
y = (1/3)x^2 - x + 3,
y' = (2/3)x - 1 = k = 1，得 x = 3, y = 3
切线方程: y = 1(x-3) + 3 = x

追问

切线方程没看懂

追答

切线方程过点(3, 3), 斜率为 1， 方程是

y - 3 = 1(x - 3), 即 y = x

追问

答案是x-y-2＝0

追答

重答： 3. y = x 斜率为 k = 1
y = (1/3)x^2 - x + 1,
y' = (2/3)x - 1 = k = 1，得 x = 3, y = 1
切线方程: y -1 = 1(x-3) ， 即 x - y - 2 = 0

追问

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