Question

若a乘(a-1)的平方加(b+1)的平方=0，则a的2004次方+b的2005次方的值为多少

求解- -

Answer 1

a(a-1)^2+(b+1)^2 =0
a=0 or 1 and b=-1
(a,b) = (0,-1) or (1,-1)
(a,b) = (0,-1)
a^2004+b^2005
= 0 -1
=-1
(a,b) = (1,-1)
a^2004+b^2005
=1 -1
=0
ie
a^2004+b^2005 = -1 or 0

追问

a可以是负数吗- 、-