Question

解方程x-2002/2003 +x-2003/2002 =2003/x-2002 +2002/x-2003

解方程（x-2002/2003）+（x-2003/2002）=（2003/x-2002）+（2002/x-2003）

Answer 1

(x-2002)/2003+(x-2003)/2002=2003/(x-2002)+2002/(x-2003)
(x-2002)/2003-2003/(x-2002)=2002/(x-2003)-(x-2003)/2002
(x^2-4005x)/[2003(x-2003)]=(4005x-x^2)/[2002(x-2002)]

x1=0

4005x^2-(4005^2+2003^2+2002^2)x+4005(2003^2+2002^2)=0
(x-4005)(4005x-2002^2-2003^2)=0

x2=4005
x3=(2003^2+2002^2)/4005= 8020013/4005

Answer 2

没有窍门可找

Answer 3

自己做很
简单的

Answer 4

没有窍门

Answer 5

答案是：
(x-2002)/2003+(x-2003)/2002=2003/(x-2002)+2002/(x-2003)
(x-2002)/2003-2003/(x-2002)=2002/(x-2003)-(x-2003)/2002
(x^2-4005x)/[2003(x-2003)]=(4005x-x^2)/[2002(x-2002)]

x1=0

4005x^2-(4005^2+2003^2+2002^2)x+4005(2003^2+2002^2)=0
(x-4005)(4005x-2002^2-2003^2)=0

x2=4005
x3=(2003^2+2002^2)/4005= 8020013/4005

Answer 6

x-2002)/2003+(x-2003)/2002=2003/(x-2002)+2002/(x-2003)
(x-2002)/2003-2003/(x-2002)=2002/(x-2003)-(x-2003)/2002
(x^2-4005x)/[2003(x-2003)]=(4005x-x^2)/[2002(x-2002)]x1=0

4005x^2-(4005^2+2003^2+2002^2)x+4005(2003^2+2002^2)=0
(x-4005)(4005x-2002^2-2003^2)=0

x2=4005
x3=(2003^2+2002^2)/4005= 8020013/4005

zhi dao le ba