Question

（y+2）²=（3y-1）²

Answer 1

（y+2）²=（3y-1）²（3y-1）²-（y+2）²=0(3y-1+y+2)(3y-1-y-2)=0

(4y+1)(2y-3)=0
y1=-1/4；y2=3/2

Answer 2

y+2=±（3y-1）即y+2=3y-1或y+2=-（3y-1），解得：y1=32，y2=-14．