1个回答
展开全部
=∫e^udsinu
=sinue^u-∫sinude^u
=sinue^u+∫e^udcosu
=sinue^u+cosue^u-∫cosude^u
=(sinu+cosu)e^u/2+C
=(x+√(1-x²))e^arcsinx/2+C
=sinue^u-∫sinude^u
=sinue^u+∫e^udcosu
=sinue^u+cosue^u-∫cosude^u
=(sinu+cosu)e^u/2+C
=(x+√(1-x²))e^arcsinx/2+C
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询