Question

已知（x-1）（X+2)分之2X-3=X-1分之A+X+2分之B.求A,B的值

Answer 1

(2x-3)/(x-1)(x+2)=A/(x-1)+B/(x+2) 通分得：(2x-3)/(x-1)(x+2)=A(x+2)/(x-1)(x+2)+B(x-1)/(x-1)(x+2) 去分母毁脊得；2x-3=A(x+2)+B(x-1) 去括号喊余激得：2x-3=Ax+2A+Bx-B 整理得：2x-3=(A+B)x+2A-B 要使上面等式成立,则要满郑袜...