设函数u(x,y)=q(x+y)+q(x-y)+定积分(x-y)到(x+y)p(t)dt,其中函数q具有二阶导数,p具有
1个回答
展开全部
u(x,y)=q(x+y)+q(x-y)+∫(x-y)到(x+y)p(t)dt
u'x=q'(x+y)+q'(x-y)+p(x+y)-p(x-y)
u'y=q'(x+y)-q'(x-y)+p(x+y)+p(x-y)
u''xx=q''(x+y)+q''(x-y)+p'(x+y)-p'(x-y)
u''yy=q''(x+y)+q'’(x-y)+p'(x+y)-p'(x-y)
选B.x的二阶偏导数=y的二阶偏导数
u'x=q'(x+y)+q'(x-y)+p(x+y)-p(x-y)
u'y=q'(x+y)-q'(x-y)+p(x+y)+p(x-y)
u''xx=q''(x+y)+q''(x-y)+p'(x+y)-p'(x-y)
u''yy=q''(x+y)+q'’(x-y)+p'(x+y)-p'(x-y)
选B.x的二阶偏导数=y的二阶偏导数
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询