Question

8*8点阵0~9显示程序（C语言）

Answer 1

#include <reg51.h>
unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
unsigned char code digittab[10][8]={
{0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00}, //0
{0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00}, //1
{0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00}, //2
{0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00}, //3
{0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00}, //4
{0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00}, //5
{0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00}, //6
{0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00}, //7
{0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00}, //8
{0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00} //9
};

unsigned int timecount;
unsigned char cnta;
unsigned char cntb;

void main(void)
{
TMOD=0x01;
TH0=(65536-1000)/256;
TL0=(65536-1000)%256;
TR0=1;
ET0=1;
EA=1;
while(1)
{;
}
}

void t0(void) interrupt 1 using 0
{
TH0=(65536-1000)/256;
TL0=(65536-1000)%256;
P3=tab[cnta];
P1=digittab[cntb][cnta];
cnta++;
if(cnta==8)
{
cnta=0;
}
timecount++;
if(timecount==333)
{
timecount=0;
cntb++;
if(cntb==10)
{
cntb=0;
}
}
}

Answer 2

这个我有啊,不过不知道什么联系你啊?

Answer 3

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