Question

安卓开发 如何获取网络中的图片

Answer 1

用自带的HttpClient，下面是我自己的库里面取出来的一个方法，我是异步ajax调用的，你要是自己用的话，把那些异步回调的去掉就行了。
url传入图片地址，outputFile是输出的文件对象，也就是说，要你先指定保存的文件位置。
只要没限制外链的图片文件应该都没问题。
/**

* 下载文件

* @param url

* @param outPut

* @param listener

* @throws AjaxException

*/

public static Responses downLoad(String url, AjaxParameters params,File outputFile, TransmitProgressLitener uploadListener) throws AjaxException{

if(params.size()>0){

url = url + "?" + Utils.encodeUrl(params);

}

Utils.amLog(url);

//httpGet连接对象

HttpGet httpRequest = new HttpGet(url);

//取得HttpClient 对象

//HttpClient httpclient = new DefaultHttpClient();

HttpClient httpclient = getNewHttpClient();

InputStream is = null;

OutputStream os= null;

try {

//请求httpClient ，取得HttpRestponse

HttpResponse httpResponse = httpclient.execute(httpRequest);

if(httpResponse.getStatusLine().getStatusCode() == HttpStatus.SC_OK){

//取得相关信息 取得HttpEntiy

HttpEntity httpEntity = httpResponse.getEntity();

//获得一个输入流

is = httpEntity.getContent();

os = new FileOutputStream(outputFile,true);

long downloaded = 0;

byte[] buffer=new byte[IO_CACHE_SIZE];

while(true){

int count=is.read(buffer);

if(count==-1){

break;

}

os.write(buffer, 0, count);

if(null!=uploadListener){

downloaded +=count;

uploadListener.updateProgress(downloaded, 0);

}

}

}

return new Responses("download suc",((DefaultHttpClient)httpclient).getCookieStore(),((DefaultHttpClient)httpclient).getCookieSpecs());

} catch (ClientProtocolException e) {

// TODO Auto-generated catch block

e.printStackTrace();

throw new AjaxException(e);

} catch (IOException e) {

// TODO Auto-generated catch block

e.printStackTrace();

throw new AjaxException(e);

} finally{

if(null!=is){

try {

is.close();

} catch (IOException e) {

throw new AjaxException(e);

}

}

if(null!=os){

try {

os.close();

} catch (IOException e) {

throw new AjaxException(e);

}

}

}

}