Question

应用公式进行计算（a+b-c-d)²

Answer 1

原式=[(a+b)-(c+d)]²
=(a+b)²-2(a+b)(c+d)+(c+d)²
=a²+2ab+b²--2ac-2ad-2bc-2bd+c²+2cd+d²

Answer 2

原式=[(a+b)-(c+d)]2
=[(a+b+c+d）(a+b-c-d)]2
=(a+b+c+d)2(a+b-c-d)2
2代表平方 望采纳

Answer 3

（a+b-c-d)²
=[（a+b)-(c+d)]²
=（a+b)²+(c+d)²-2(a+b)(c+d)
=a²+2ab+b²+c²+2cd+d²-2(ac+ad+bc+bd)
=a²+2ab+b²+c²+2cd+d²-2ac-2ad-2bc-2bd
=a²+b²+c²+d²+2ab+2cd-2ac-2ad-2bc-2bd

Answer 4

（a+b-c-d)²
=【（a+b）-（c+d）】^2
=(a+b)^2-2(a+b)(c+d)+(c+d）^2
=a^2+2ab+b^2-2ac-2ad-2bc-2bd+c^2+2cd+d^2
=a^2+b^2+c^2+d^2+2ab+2cd-2ac-2ad-2bc-2bd