求偏导数,求相细步骤及所用公式,及时采纳
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F(x,y)=1/π^2 * (π/2 + arctanx) * (π/2 + arctan(2y))
先求:
aF/ax
=1/π^2 * (π/2 + arctanx)' * (π/2 + arctan(2y))
=1/π^2 * 1/(1+x^2) * (π/2 + arctan(2y))
进一步,
a^2F/axay
=a(aF/ax)/ay
=a[1/π^2 * 1/(1+x^2) * (π/2 + arctan(2y))]/ay
=1/π^2 * 1/(1+x^2) * (π/2 + arctan(2y))'
=1/π^2 * 1/(1+x^2) * 2/(1+4y^2)
=2/π^2 * 1/(1+x^2) * 1/(1+4y^2)
有不懂欢迎追问
先求:
aF/ax
=1/π^2 * (π/2 + arctanx)' * (π/2 + arctan(2y))
=1/π^2 * 1/(1+x^2) * (π/2 + arctan(2y))
进一步,
a^2F/axay
=a(aF/ax)/ay
=a[1/π^2 * 1/(1+x^2) * (π/2 + arctan(2y))]/ay
=1/π^2 * 1/(1+x^2) * (π/2 + arctan(2y))'
=1/π^2 * 1/(1+x^2) * 2/(1+4y^2)
=2/π^2 * 1/(1+x^2) * 1/(1+4y^2)
有不懂欢迎追问
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老师,这密密麻麻的太乱了,我都没看懂,麻烦老师手写一下发个图片过来行不?
老师,这密密麻麻的太乱了,我都没看懂,麻烦老师手写一下发个图片过来行不?
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