Question

一道高中数学题 求学霸！！！解答

Answer 1

根据
，b/sinB=a/sinA,a=2√3，
A=π/3，B=x,b=4sinx,c/sinC=a/sinA,
c=2√3/(√3/2)*sinC=4sinC=4sin(A+B)
=4sin(π/3+x)=2√3cosx+2sinx
周长:y=a+b+c=2√3+4sinx+2√3cosx+2sinx
=2√3+6sinx+2√3cosx
0<x<2π/3,
y=2√3+2√3(√3sinx+cosx)
=2√3+4√3[sinx*cos(π/6)+cosx*sin(π/6)]
=2√3+4√3sin(x+π/6)
当sin(x+π/6)=1时函数有最大值，
y=6√3