Question

数学题:1/a+6/b=根号5,求求b(a-b)分之a-a(a-b)分之b的值

是6/b不是1/b

Answer 1

1/a+6/b=根号5
1/a+6/b=√5
1/a=√5-6/b=(√5b-6)/b

b(a-b)分之a-a(a-b)分之b
=a/[b(a-b)]-b/[a(a-b)]
=a²/[ab(a-b)]-b²/[ab(a-b)]
=(a²-b²)/[ab(a-b)]
=(a-b)(a+b)/[ab(a-b)]
=(a+b)/(ab)
=1/b+1/a
=1/b+(√5b-6)/b
=(1+√5b-6)/b
=(√5b-5)/b或
=√5-5/b

Answer 2

a/b(a-b)-b/a(a-b)通分后=(a²-b²)/ab(a-b)=(a-b)(a+b)/ab(a-b)=(a+b)/ab=a/ab+b/ab=1/a+1/b
请问是不是还有别的条件呢？

追问

没有了 只有a不等于b了

Answer 3

后面化简是1/a 1/b