这道电路分析题怎么做?
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2015-04-06
展开全部
u = u1 + u2 - u3
= 80sin(ωt + 120°) + 60sin(ωt + 60°) - 100sin(ωt - 30°)
= 80sin(ωt)*cos120° + 80cos(ωt)*sin120° + 60sin(ωt)*cos60° + 60cos(ωt)*sin60° - 100sin(ωt)*cos(-30°) - 100cos(ωt)*sin(-30°)
= sin(ωt)*[80cos120° + 60cos60° - 100cos(-30°)] + cos(ωt)*[80sin120° + 60sin60° - 100sin(-30°)]
= sin(ωt)*[-40 + 30 - 50√3 ] + cos(ωt)*[40√3 + 30√3 + 50]
= sin(ωt)*(-10 - 50√3) + cos(ωt)*(70√3 + 50)
= 10*[sin(ωt)*(-1 - 5√3) + cos(ωt)*(7√3 + 5)]
= 10*√(248 + 80√3) * [sin(ωt)*(-1-5√3)/√(248 + 80√3) + cos(ωt)*(7√3 + 5)/√(248 + 80√3)]
≈ 196.6 * [sin(ωt)*(-0.4913) + cos(ωt)*(0.8710)]
= 196.6 * [sin(ωt)*cos(119.43) + cos(ωt)*sin(119.43°)]
= 196.6 * sin(ωt + 119.43°)
= 80sin(ωt + 120°) + 60sin(ωt + 60°) - 100sin(ωt - 30°)
= 80sin(ωt)*cos120° + 80cos(ωt)*sin120° + 60sin(ωt)*cos60° + 60cos(ωt)*sin60° - 100sin(ωt)*cos(-30°) - 100cos(ωt)*sin(-30°)
= sin(ωt)*[80cos120° + 60cos60° - 100cos(-30°)] + cos(ωt)*[80sin120° + 60sin60° - 100sin(-30°)]
= sin(ωt)*[-40 + 30 - 50√3 ] + cos(ωt)*[40√3 + 30√3 + 50]
= sin(ωt)*(-10 - 50√3) + cos(ωt)*(70√3 + 50)
= 10*[sin(ωt)*(-1 - 5√3) + cos(ωt)*(7√3 + 5)]
= 10*√(248 + 80√3) * [sin(ωt)*(-1-5√3)/√(248 + 80√3) + cos(ωt)*(7√3 + 5)/√(248 + 80√3)]
≈ 196.6 * [sin(ωt)*(-0.4913) + cos(ωt)*(0.8710)]
= 196.6 * [sin(ωt)*cos(119.43) + cos(ωt)*sin(119.43°)]
= 196.6 * sin(ωt + 119.43°)
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