Question

java JPanel 怎么让jpanel平滑移动

for(int x=-430;x<=0;x+=2){ jf.repaint(); try { Thread.sleep(1); } catch (InterruptedException e1) { // TODO 自动生成的 catch 块 e1.printStackTrace(); } jf.setLocation(x,0); System.out.println("x");

写在主函数可以完成。
但这代码写在类中，无法实现按按钮让它缓慢移动。而是直接到延时后直接在指定位置出现。
但怎么实现类中完成鼠标事件执行。





Answer 1

附一个简单的示例代码

import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.*;

/**
*
* @author Jeky
*/
public class MainFrame extends JFrame {

private JPanel movePanel;
private JButton button;

public MainFrame() {
movePanel = new JPanel();
movePanel.setBorder(BorderFactory.createRaisedBevelBorder());
movePanel.setBounds(new Rectangle(50, 50, 50, 50));

button = new JButton("移动");
button.addActionListener(new ActionListener() {

public void actionPerformed(ActionEvent e) {
Rectangle bounds = movePanel.getBounds();
Point location = bounds.getLocation();
location.x+=5;
location.y+=5;
bounds.setLocation(location);
movePanel.setBounds(bounds);
}
});

JPanel center = new JPanel();
center.setLayout(null);
center.add(movePanel);

JPanel south = new JPanel();
south.setLayout(new FlowLayout(FlowLayout.CENTER));
south.add(button);

this.getContentPane().add(center,BorderLayout.CENTER);
this.getContentPane().add(south,BorderLayout.SOUTH);
this.setSize(300, 300);
this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
this.setVisible(true);
}

public static void main(String[] args) {
new MainFrame();
}
}

追问

已看过，不是要这个效果