Question

php判断数组包含另一个数组

$tids= array ( 2=> '19', 3 => '13', );
$ids=array ( 0 => '96', 1 => '116', 2 => '13', 3 => '19' );
怎么判断$ids是否包含$tids

Answer 1

//主要用到php的in_array函数，代码示例如下
$tids= array ( 2=> '19', 3 => '13', );
$ids=array ( 0 => '96', 1 => '116', 2 => '13', 3 => '19' );
$flag=true;
foreach($tids as $v){
if(!in_array($v,$ids)){
$flag=false;
break;
}
}
if($flag){
echo '$b数组包含$a数组';
}else{
echo '$b数组不包含$a数组';
}

Answer 2

$tids= array ( 2=> '19', 3 => '13', );
$ids=array ( 0 => '96', 1 => '116', 2 => '13', 3 => '19' );
$flag = true;
foreach( $tids as $val ){
if( !in_array($val, $ids) ){
$flag = false;
break;
}
}
if( $flag ){
echo "包含";
}else{
echo "不包含";
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Answer 3

$tids= array ( 2=> '19', 3 => '13', );
$ids=array ( 0 => '96', 1 => '116', 2 => '13', 3 => '19' );
$flag = true;
foreach( $tids as $val ){
    if( !in_array($val, $ids) ){
        $flag = false;
        break;
    }
}
if( $flag ){
    echo "包含";
}else{
    echo "不包含";
}

Answer 4

echo array_intersect(array_keys($ids),array_keys($tids))===array_keys($tids)?'y':'n';