Question

二元二次方程x²-2xy-8y²=0可以化为两个一次方程,这两个一次方程:

二元二次方程x²-2xy-8y²=0可以化为两个一次方程，这两个一次方程：

Answer 1

x²-2xy-8y²=(x-4y)(x+2y)=0
这两个一次方程：
x-4y=0
或x+2y=0

Answer 2

x^2-2xy-8y^2=0
x^2-2xy+y^2-9y^2=(x-y)^2-(3y)^2
=(x-y-3y)(x-y+3y)
=(x-4y)(x+2y)=0
x-4y=0
x+2y=0

Answer 3

解：(x-4y)(x+2y)=0
x-4y=0
x+2y=0

Answer 4

因式分解得
(x-4y)(x+2y)=0
所以是
x-4y=0或者
x+2y=0

Answer 5

x²-2xy-8y²=0

(x-4y)(x+2y)=0

Answer 6

(x-4y)(x+2y)=0
x-4y=0或x+2y=0