计算题求具体过程急急急
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=√(xy)(√x-√y)/[√(xy)(√x+√y)]-√(xy)(√x+√y)/[√(xy)(√x-√y)]
=[(√x-√y)(√x-√y)-(√x+√y)(√x+√y)]/[(√x+√y)(√x-√y)]
=[x-2√(xy)+y-x-2√(xy)-y]/(x-y)
=-4√(xy)/(x-y)
=[(√x-√y)(√x-√y)-(√x+√y)(√x+√y)]/[(√x+√y)(√x-√y)]
=[x-2√(xy)+y-x-2√(xy)-y]/(x-y)
=-4√(xy)/(x-y)
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