数学题 求未知数
一个3心淘宝买家购物次数在(41-90之间)给出的好评率是80.56%,求他一共给过多少个差评,一共购物多少次、。求算法。谢谢...
一个3心淘宝买家 购物次数在(41-90之间) 给出的好评率是80.56% ,求他一共给过多少个差评,一共购物多少次、。求算法。谢谢
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设总共购物x次,x是整数,好评次数:
80.56%x,也是整数,或者最接近的整数。
80.56%(41~90)=33.0296~72.504
整数问题,可以用连分数来解
80.56%=8056/10000=1007/1250=(19×53)/(2×5^4)
=1/(1+243/1007)
=1/(1+1/(4+35/243))
=1/(1+1/(4+1/(6+33/35)))
=1/(1+1/(4+1/(6+1/(1+2/33))))
=1/(1+1/(4+1/(6+1/(1+1/(16+1/2)))))
渐进分数:
1/(1+0)=1
1/(1+1/4)=4/5
1/(1+1/(4+1/6))=25/31
1/(1+1/(4+1/(6+1/1)))=29/36
1/(1+1/(4+1/(6+1/(1+1/16))))=489/607
1/(1+1/(4+1/(6+1/(1+1/(16+1/2)))))=1007/1250
在分母为41~90之间,只有29/36
x=36,好评29,好评率=29/36=80.5555555555555556%≈80.56%
差评36-29=7
80.56%x,也是整数,或者最接近的整数。
80.56%(41~90)=33.0296~72.504
整数问题,可以用连分数来解
80.56%=8056/10000=1007/1250=(19×53)/(2×5^4)
=1/(1+243/1007)
=1/(1+1/(4+35/243))
=1/(1+1/(4+1/(6+33/35)))
=1/(1+1/(4+1/(6+1/(1+2/33))))
=1/(1+1/(4+1/(6+1/(1+1/(16+1/2)))))
渐进分数:
1/(1+0)=1
1/(1+1/4)=4/5
1/(1+1/(4+1/6))=25/31
1/(1+1/(4+1/(6+1/1)))=29/36
1/(1+1/(4+1/(6+1/(1+1/16))))=489/607
1/(1+1/(4+1/(6+1/(1+1/(16+1/2)))))=1007/1250
在分母为41~90之间,只有29/36
x=36,好评29,好评率=29/36=80.5555555555555556%≈80.56%
差评36-29=7
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