Question

程序问题：myeclipse开发hibernate

程序问题：myeclipse开发hibernate:
错误：
javax.servlet.ServletException: could not insert: [com.mapping.Userlist]
org.apache.struts.action.RequestProcessor.processException(RequestProcessor.java:545)
org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:486)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525)
javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
程序代码：
RegisterForm registerForm = (RegisterForm) form;
String userName=registerForm.getUserName();
String password=registerForm.getPassword();
Session session=SessionFactory.currentSession();
Transaction tx=session.beginTransaction();
Userlist ulist=new Userlist();
ulist.setName(userName);
ulist.setPassword(password);
session.save(ulist);
执行到倒数第二句都没有问题。
Userlist.hbm.xml:
<hibernate-mapping package="com.mapping">
<class name="Userlist" table="userlist">
<id name="name" column="name" type="java.lang.String">
<generator class="native"/>
</id>
<property name="password" column="password" type="java.lang.String" not-null="true" />
</class>
</hibernate-mapping>
后面有：
tx.commit();
SessionFactory.closeSession();
根本就没有openSession()的方法阿

Answer 1

sorry
少写了一点东西
首先要得到 SessionFactory
Configuration config=new Configuration();
SessionFactory sf = config.buildSessionFactory();
Session session=sf.openSession();
然后再执行你的insert语句 试试