Question

(a-b+c)乘(a+b-c)怎么算？

如（2z-4y+1)乘（2z+4y-1)得多少？？谢谢各位了

Answer 1

(a-b+c)*(a+b-c)
=a²+ab-ac-ab-b²+bc+ac+bc-c²
=a²-b²+2bc-c²

(2z-4y+1)*(2z+4y-1)
=4z²+8yz-2z-8yz-16y²+4y+2z+4y-1
=4z²-16²+8y-1

就是按照四则运算的规律哈～

Answer 2

（2z-4y+1)×（2z+4y-1)
=[2z-(4y-1)]×[2z+(4y-1)]
=(2z)²-(4y-1)²
=4z²-(16y²-8y+1)
=4z²-16y²+8y-1

(a-b+c)×(a+b-c)
=[a-(b-c)]×[a+(b-c)]

=a²-b²-c²+2ab就可以了
是平方差公式嘛

Answer 3

（2z-4y+1)×（2z+4y-1)
=[2z-(4y-1)]×[2z+(4y-1)]
=(2z)²-(4y-1)²
=4z²-(16y²-8y+1)
=4z²-16y²+8y-1

Answer 4

回答 共 6 条
（2z-4y+1)×（2z+4y-1)
=[2z-(4y-1)]×[2z+(4y-1)]
=(2z)²-(4y-1)²
=4z²-(16y²-8y+1)
=4z²-16y²+8y-1

Answer 5

(a-b+c)(a+b-c)
=[a-(b-c)[a+(b-c)]
=a²-(b-c)²
=a²-(b²-2bc+c²)
=a²-b²-c2+2bc

（2z-4y+1)（2z+4y-1)
=[2z-(4y-1)][2z+(4y-1)]
=(2z)²-(4y-1)²
=4z²-(16y²-8y+1)
=4z²-16y²+8y-1