Question

因式分解

1.已知x-2y+3=0，求x的平方-（4y+1）x+4y的平方+2y
2.（1-a的平方）（1-b的平方）+4ab
快一点
在21:30前要答案

Answer 1

x-2y+3=0
x-2y=-3
x²-（4y+1）x+4y²+2y
=x²-4xy+4y²-(x-2y)
=(x-2y)²-(x-2y)
=(x-2y)(x-2y-1)
=-3*(-4)
=12

（1-a的平方）（1-b的平方）+4ab
=1-a²-b²+(ab)²+4ab
=(ab)²+2ab+1-(a²+b²-2ab)
=(ab+1)²-(a-b)²
=(ab+1+a-b)(ab+1-a+b)

Answer 2

x²-(4y+1)x+4y²+2y
=(x²-4xy+4y²)-x+2y
=(x-2y)²-(x-2y)
=(x-2y)(x-2y-1)
=-3*(-3-1)
=-12

(1-a²)(1-b²)+4ab
=a²b²+1+2ab-a²-b²+2ab
=(ab+1)²-(a-b)²
=(ab+1-a+b)(ab+1+a-b)