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1/[(x-1)(x-3)]≡ A/(x-1) + B/(x-3)
=>
1≡ A(x-3) + B(x-1)
x=1, => A =-1/2
x=3, => B =1/2
ie
1/[(x-1)(x-3)]≡ (1/2) [ 1/(x-3) - 1/(x-1)]
=>
1≡ A(x-3) + B(x-1)
x=1, => A =-1/2
x=3, => B =1/2
ie
1/[(x-1)(x-3)]≡ (1/2) [ 1/(x-3) - 1/(x-1)]
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