Question

高数，定积分，求解

求解第（3）小题

Answer 1

(3)=(1/2)*积分符号d(1-x^2)/√(1-x^2)

=(1/2)*2*√(1-x^2)+C

=√(1-x^2)+C 丨(0，1)

=0-1=-1

Answer 2

(3)
∫(0->1) -x/√(1-x^2) dx
=(1/2)∫(0->1) d(1-x^2)/√(1-x^2)
=[√(1-x^2)]|(0->1)
=-1